3.2.39 \(\int ((-3+x) x)^{2/3} (-3+2 x) \, dx\)

Optimal. Leaf size=16 \[ \frac {3}{5} (-((3-x) x))^{5/3} \]

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Rubi [A]  time = 0.01, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {1588} \begin {gather*} \frac {3}{5} (-(3-x) x)^{5/3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((-3 + x)*x)^(2/3)*(-3 + 2*x),x]

[Out]

(3*(-((3 - x)*x))^(5/3))/5

Rule 1588

Int[(Pp_)*(Qq_)^(m_.), x_Symbol] :> With[{p = Expon[Pp, x], q = Expon[Qq, x]}, Simp[(Coeff[Pp, x, p]*x^(p - q
+ 1)*Qq^(m + 1))/((p + m*q + 1)*Coeff[Qq, x, q]), x] /; NeQ[p + m*q + 1, 0] && EqQ[(p + m*q + 1)*Coeff[Qq, x,
q]*Pp, Coeff[Pp, x, p]*x^(p - q)*((p - q + 1)*Qq + (m + 1)*x*D[Qq, x])]] /; FreeQ[m, x] && PolyQ[Pp, x] && Pol
yQ[Qq, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int ((-3+x) x)^{2/3} (-3+2 x) \, dx &=\frac {3}{5} (-((3-x) x))^{5/3}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 13, normalized size = 0.81 \begin {gather*} \frac {3}{5} ((x-3) x)^{5/3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((-3 + x)*x)^(2/3)*(-3 + 2*x),x]

[Out]

(3*((-3 + x)*x)^(5/3))/5

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IntegrateAlgebraic [A]  time = 0.01, size = 13, normalized size = 0.81 \begin {gather*} \frac {3}{5} ((x-3) x)^{5/3} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((-3 + x)*x)^(2/3)*(-3 + 2*x),x]

[Out]

(3*((-3 + x)*x)^(5/3))/5

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fricas [A]  time = 0.67, size = 11, normalized size = 0.69 \begin {gather*} \frac {3}{5} \, {\left (x^{2} - 3 \, x\right )}^{\frac {5}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((-3+x)*x)^(2/3)*(-3+2*x),x, algorithm="fricas")

[Out]

3/5*(x^2 - 3*x)^(5/3)

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giac [A]  time = 0.15, size = 11, normalized size = 0.69 \begin {gather*} \frac {3}{5} \, {\left (x^{2} - 3 \, x\right )}^{\frac {5}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((-3+x)*x)^(2/3)*(-3+2*x),x, algorithm="giac")

[Out]

3/5*(x^2 - 3*x)^(5/3)

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maple [A]  time = 0.00, size = 14, normalized size = 0.88 \begin {gather*} \frac {3 \left (x -3\right ) \left (\left (x -3\right ) x \right )^{\frac {2}{3}} x}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((x-3)*x)^(2/3)*(-3+2*x),x)

[Out]

3/5*(x-3)*x*((x-3)*x)^(2/3)

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maxima [A]  time = 0.43, size = 9, normalized size = 0.56 \begin {gather*} \frac {3}{5} \, \left ({\left (x - 3\right )} x\right )^{\frac {5}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((-3+x)*x)^(2/3)*(-3+2*x),x, algorithm="maxima")

[Out]

3/5*((x - 3)*x)^(5/3)

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mupad [B]  time = 3.66, size = 13, normalized size = 0.81 \begin {gather*} \frac {3\,x\,{\left (x\,\left (x-3\right )\right )}^{2/3}\,\left (x-3\right )}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x - 3)*(x*(x - 3))^(2/3),x)

[Out]

(3*x*(x*(x - 3))^(2/3)*(x - 3))/5

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sympy [A]  time = 4.25, size = 10, normalized size = 0.62 \begin {gather*} \frac {3 \left (x \left (x - 3\right )\right )^{\frac {5}{3}}}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((-3+x)*x)**(2/3)*(-3+2*x),x)

[Out]

3*(x*(x - 3))**(5/3)/5

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